$$\cos(90^\circ - \delta) = \cos(90^\circ - \phi)\cos(90^\circ - a) + \sin(90^\circ - \phi)\sin(90^\circ - a)\cos A$$
Spherical trigonometry bridges these two systems using the and the Local Hour Angle (LHA) . To find Altitude ( ):
$$\cos(90^\circ - \delta) = \cos(90^\circ - \phi)\cos(90^\circ - a) + \sin(90^\circ - \phi)\sin(90^\circ - a)\cos A$$
Spherical trigonometry bridges these two systems using the and the Local Hour Angle (LHA) . To find Altitude ( ): spherical astronomy problems and solutions
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