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[ (\nabla \times \mathbfF) \cdot \mathbfn = (-1,-1,-1) \cdot \frac(1,1,1)\sqrt3 = -\frac3\sqrt3 = -\sqrt3 ] So RHS = ( \iint_S (-\sqrt3) , dS = -\sqrt3 \times \text(surface area) ). If you are looking for solutions or specific